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battle of sexes
例、性别战(battle of sexes) 妻子 B F B 丈夫 F 1,2 0,0 0,0 2,1 7、“Nash威胁”无名氏定理 o 定理(Friedman,1971):设a*为阶段 博弈的Nash均衡,相...
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...偏离 对开 -1 , -1 2 , 0 偏离 0 , 2 1 , 1 DSE=NE7500 ,
, 5500例4两性战争(Battle of Sexes):女球赛2 , 10 , 00 , 01 , 2男球赛音乐会音乐会纳什均衡 (C) Professor Ho-Mou WuSpring 2009Games2-26以上考虑的是纯粹策略 (Pur...
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...? 责任明晰:成本明确 ? 成本和收益皆内在化——行为保持在有效 率的水平 ? 同时激励人们创造 ? 性别之争(Battle of Sexes) 丈夫 肥皂剧 篮球 妻 肥皂剧 子 篮球 2,1 0,0 0,0 1,2 上策均衡的局限 不是所有的完全信息静态博弈中的博弈方都存在上策 的...
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...主要基础,运用囚徒困境博弈(prisoners’ dilemma)、序贯决策博弈(sequential-move games)、性别之战博弈(battle of sexes),尝试运用于新城机制之探讨。
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性别战博弈
性别对战博弈
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Battle of the Sexes: Are the Worst Hurricanes Male or Female?
两性之争:最恶劣的那些飓风是男性还是女性?
It is the ultimate battle of the sexes - and women usually win.
这是两性之间的终极较量——而且通常女性获胜。
And certainly, there are those whose change of orientation is undoubtedly fuelled by a sense of exasperation with a battle of the sexes within the confines of a home.
当然同时,那些变化了的方向的举动无疑是来自一对恼怒了的男女及出于对她们家庭束缚战的抗争。
That's good. So this game's called The Battle of the Sexes and we'll see it in various forms over the course of the semester.
没错,就叫性别大战,我们会在这学期的课程中陆续接触到的
Battle of the Sexes.
它叫性别大战
The classic works of Ernst Lubitsch, Howard Hawks and Preston Sturges married witty verbal banter with lowbrow physical slapstick, finding their focus in the battle of the sexes and making a mockery of the puritanical Production Code.
Whether or not the equine 'battle of the sexes' ever materializes, the racing world has one more season to savor the exploits of the giant bay with the white star before his career follows its inevitable trajectory towards the breeding shed.
Relieved of the burden of nomadic living, men and women slowly began the battle of the sexes.
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感谢您的反馈,我们会尽快进行适当修改!From Wikipedia, the free encyclopedia
Battle of the Sexes 1
Battle of the Sexes 2
In , battle of the sexes (BoS) is a two-player . Imagine a couple that agreed to meet this evening, but cannot recall if they will be attending the opera or a football match (and the fact that they forgot is ). The husband would prefer to go to the football game. The wife would rather go to the opera. Both would prefer to go to the same place rather than different ones. If they cannot communicate, where should they go?
labeled "Battle of the Sexes (1)" is an example of Battle of the Sexes, where the wife chooses a row and the husband chooses a column. In each cell, the first number represents the payoff to the wife and the second number represents the payoff to the husband.
This representation does not account for the additional harm that might come from not only going to different locations, but going to the wrong one as well (e.g. he goes to the opera while she goes to the football game, satisfying neither). To account for this, the game is sometimes represented as in "Battle of the Sexes (2)".
Some authors refer to the game as Bach or Stravinsky and designate the players simply as Player 1 and Player 2, rather than assigning gender.
This game has two
, one where both go to the opera and another where both go to the football game. There is also a
Nash equilibrium in both games, where the players go to their preferred event more often than the other. For the payoffs listed in the first game, each player attends their preferred event with probability 3/5.
This presents an interesting case for
since each of the Nash equilibria is deficient in some way. The two pure strategy Nash e one player consistently does better than the other. The mixed strategy Nash equilibrium (when it exists) is inefficient. The players will miscoordinate with probability 13/25, leaving each player with an expected return of 6/5 (less than the return one would receive from constantly going to one's less favored event).
One possible resolution of the difficulty involves the use of a . In its simplest form, if the players of the game have access to a commonly observed randomizing device, then they might decide to correlate their strategies in the game based on the outcome of the device. For example, if the couple could flip a coin before choosing their strategies, they might agree to correlate their strategies based on the coin flip by, say, choosing football in the event of heads and opera in the event of tails. Notice that once the results of the coin flip are revealed neither the husband nor wife have any incentives to alter their proposed actions – that would result in miscoordination and a lower payoff than simply adhering to the agreed upon strategies. The result is that perfect coordination is always achieved and, prior to the coin flip, the expected payoffs for the players are exactly equal.
The equilibria may be found by a generic Nash equilibrium solver such as the . But BoS solutions are also simple enough to be found though a few steps of simple algebra.
Let us calculate the four probabilities for the actions of the individuals (Man and Woman), which depend on their expectations of the behaviour of the other, and the relative payoff from each action. These four probabilities are:
The Man goes to the Football (resp. Opera), denoted by MF (resp. MO).
The Woman goes to the Football (resp. Opera), denoted by WF (resp. WO).
The Probability that the Man goes to the Football game, MF, equals the payoff if he does (whether or not the woman does), divided by the same payoff plus the payoff if he goes to the opera instead:
{\displaystyle M_{F}={\frac {W_{O}+3W_{F}}{W_{O}+3W_{F}+2W_{O}+0W_{F}}}={\frac {W_{O}+3W_{F}}{3W_{O}+3W_{F}}}}
We know that she either goes to one or the other, so
{\displaystyle W_{O}+W_{F}=1}
{\displaystyle M_{F}={\tfrac {1}{3}}(W_{O}+3W_{F})}
Similarly:
{\displaystyle {\begin{aligned}M_{O}&={\tfrac {2}{3}}W_{O}\\W_{F}&={\tfrac {2}{3}}M_{F}\\W_{O}&={\tfrac {1}{3}}(3M_{O}+M_{F})\end{aligned}}}
This forms a set of simultaneous equations. We can solve these, starting with
{\displaystyle M_{F}}
for example, by substituting in the equations above:
{\displaystyle {\begin{aligned}M_{F}&={\tfrac {1}{3}}\left({\tfrac {1}{3}}(3M_{O}+M_{F})+3\left({\tfrac {2}{3}}M_{F}\right)\right)\\&={\tfrac {1}{3}}\left(M_{O}+{\tfrac {7}{3}}M_{F}\right)\\&={\tfrac {1}{3}}\left(1+{\tfrac {4}{3}}M_{F}\right)&&M_{O}+M_{F}=1\end{aligned}}}
Solving the last equation for
{\displaystyle M_{F}}
{\displaystyle M_{F}={\tfrac {3}{5}}}
Knowing that
{\displaystyle M_{F}+M_{O}=1}
, we deduce:
{\displaystyle M_{O}=1-{\tfrac {3}{5}}={\tfrac {2}{5}}}
{\displaystyle W_{F}={\tfrac {2}{3}}M_{F}={\tfrac {2}{5}}}
{\displaystyle W_{O}=1-{\tfrac {2}{5}}={\tfrac {3}{5}}}
Then we can calculate the probability of coordination
{\displaystyle P_{c}}
(that M and W do the same thing, independently), as:
{\displaystyle P_{c}=M_{F}W_{F}+M_{O}W_{O}={\tfrac {3}{5}}{\tfrac {2}{5}}+{\tfrac {2}{5}}{\tfrac {3}{5}}={\tfrac {12}{25}}}
And the probability of miscoordination
{\displaystyle P_{m}}
(that M and W do different things, independently):
{\displaystyle P_{m}=M_{F}W_{O}+M_{O}W_{F}={\tfrac {3}{5}}{\tfrac {3}{5}}+{\tfrac {2}{5}}{\tfrac {2}{5}}={\tfrac {13}{25}}}
And just to check our probability working:
{\displaystyle P_{c}+P_{m}={\tfrac {12}{25}}+{\tfrac {13}{25}}={\tfrac {25}{25}}=1}
So the probability of miscoordination is
{\displaystyle {\tfrac {13}{25}}}
as stated above.
The expected payoff E for each individual (
{\displaystyle E_{m}}
{\displaystyle E_{w}}
) is the probability of each event multiplied by the payoff if it happens. For example, the Probability that the man goes to football and the Woman goes to football multiplied by the Expected payoff to the man if that happens (
{\displaystyle E_{mmfwf}}
{\displaystyle {\begin{aligned}E_{m}&=M_{F}W_{F}E_{mmfwf}+M_{F}W_{O}E_{mmfwo}+M_{O}W_{O}E_{mmowo}+M_{O}W_{F}E_{mmowf}\\&={\tfrac {3}{5}}{\tfrac {2}{5}}3+{\tfrac {3}{5}}{\tfrac {3}{5}}1+{\tfrac {2}{5}}{\tfrac {3}{5}}2+{\tfrac {2}{5}}{\tfrac {2}{5}}0={\tfrac {39}{25}}\end{aligned}}}
Which is not the same as the
{\displaystyle {\tfrac {6}{5}}}
stated above!
For comparison, let us assume that the man always goes to football and the woman, knowing this, chooses what to do based on revised probabilities and expected values to her:
{\displaystyle M_{F}=1}
{\displaystyle M_{O}=0}
{\displaystyle W_{F}={\tfrac {2}{3}}M_{F}={\tfrac {2}{3}}}
{\displaystyle W_{O}=1-{\tfrac {2}{3}}={\tfrac {1}{3}}}
{\displaystyle {\begin{aligned}Em&=M_{F}W_{F}E_{mmfwf}+M_{F}W_{O}E_{mmfwo}+M_{O}W_{O}E_{mmowo}+M_{O}W_{F}E_{mmowf}\\&=1{\tfrac {2}{3}}3+1{\tfrac {1}{3}}1+0{\tfrac {1}{3}}2+0{\tfrac {2}{3}}0={\tfrac {7}{3}}\end{aligned}}}
This is symmetric for
{\displaystyle E_{w}}
if the woman always goes to the opera and the man chooses randomly with probabilities based on the expected outcome, due to the symmetry in the value table. But if both players always do the same thing (both have simple strategies), the payoff is just 1 for both, from the table above.
Given the above, how should players choose which of the three Nash equilibria to actually play in practice? One (contested)
is that if they are both identical then they must arrive at the same rational answer, if one exists, and the only way to do this is to choose the mixed strategy equilibrium because it is symmetric. (citation needed).
Interesting strategic changes can take place in this game if one allows one player the option of "" – that is, allowing that player to destroy some of her utility. Consider the version of Battle of the Sexes pictured here (called Unburned). Before making the decision the row player can, in view of the column player, choose to set fire to 2 points making the game Burned pictured to the right. This results in a game with four strategies for each player. The row player can choose to burn or not burn the money and also choose to play Opera or Football. The column player observes whether or not the row player burns and then chooses either to play Opera or Football.
then one arrives at a unique solution where the row player does not burn the money and plays Opera and where the column player plays Opera. The odd thing about this result is that by simply having the opportunity to burn money (but not actually using it), the row player is able to secure her favored equilibrium. The reasoning that results in this conclusion is known as
and is somewhat controversial. In brief, by choosing not to burn money, the player is indicating she expects an outcome that is better than any of the outcomes available in the "burned" version, and this conveys information to the other party about which branch she will take.
Battle of the Sexes Game with Ambiguity
Decisions are said to be
if there are no objective probabilities given and it is difficult or impossible to assign subjective probabilities to events. Kelsey and le Roux (2015) report an experimental test of the influence of ambiguity on behaviour in a Battle of Sexes game which has an added safe strategy, R, available for Player 2 (see Table). The paper studies the behaviour of subjects in the presence of ambiguity and attempts to determine whether subjects playing the Battle of Sexes game prefer to choose an ambiguity safe option.
The value of x, which is the safe option available to Player 2, varies in the range 60-260. For some values of x, the safe strategy (option R) is dominated by a mixed strategy of L and M, and thus would not be played in a . For some higher values of x the game is . The effect of
is to make R (the ambiguity-safe option) attractive for Player 2. R is never chosen in Nash equilibrium for the parameter values considered. However it may be chosen when there is ambiguity. Moreover for some values of x, the games are dominance solvable and R is not part of the equilibrium strategy.
It was found that R is chosen quite frequently by subjects. While the Row Player randomises 50:50 between her strategies, the Column Player shows a marked preference for avoiding ambiguity and choosing his ambiguity-safe strategy. Thus, the results provide evidence that ambiguity influences behaviour in the games.
(1957) Games and Decisions: An Introduction and Critical Survey, Wiley & Sons. (see Chapter 5, section 3).
Fudenberg, D. and
(1991) Game theory, MIT Press. (see Chapter 1, section 2.4)
Kelsey, D. and S. le Roux (2015): An Experimental Study on the Effect of Ambiguity in a Coordination Game, Theory and Decision.
Osborne, Rubinstein (1994). A course in game theory. The MIT Press.
For a detailed explanation, see
p8 Section 4.5.
For a detailed explanation, see .
by Elmer G. Wiens
: Hidden categories:性别之战(Battle of the Sexes)-电影-腾讯视频
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Battle of the Sexes电影
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伊丽莎白·苏,日出生于美国特拉华州威明顿一个富有、有着良好教育的家庭。有三个兄弟。读四年级时父母离婚。早年在哈佛大学攻读法律,后来就读于韦斯理女子大学。在大学学习期间,伊丽莎白经常在一些商业电视片中出任角色,从而为自己挣一...
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