相关词典网站：hit or miss
不论成功与否；无计划的；漫不经心的
不论成功与否
漫不经心的
特定匹配操作
Miss(不管好歹), 此释义来源于网络辞典。
基于1个网页-
击中击不中变换
击中与击不中变换
击中击不中变换
不论命中不命中
为所欲为的
击中击不中
漫不经心的
形态交离转换
击不中变换
击中击不中变换
漫无主义者
有时有阵雨
更多收起网络短语
hit or miss
dependent upon or characterized by chance
以上来源于:
hit or miss
无论成功与否
漫无目标地
以上来源于：《21世纪大英汉词典》
Of course that’s if the baby is willing to show itself to the camera which is always hit or miss.
当然，这取决于婴儿是否愿意把它们展示给摄影机，因为它们经常漫无目的。
Existing frameworks have been proven very successful when designing bridges and other engineered systems but have been hit or miss propositions when it comes to software for business systems.
在设计桥梁和其他工程系统时，现有框架已被证明非常成功。 但在使用它来为业务系统开发软件时，却碰了壁。
Keeping the information between the two tools synchronized was a hit or miss proposition.
保持这两个工具间的信息同步是一个漫无目的的主张。
So it's this interesting scenario where it's probably hit or miss, certainly early on and as one of the clips they are indicated, these are the kinds of things where computers ideally have to learn overtime.
因此，这是一个有意思的事情,因为它有可能是投其所好或者不对其胃口，当然继续,正如其中一个短片所示，这些东西需要计算机,花一些时间去学习。
Such books have a short shelf life and can be hit or miss.
Some people make money by price speculation, but that is hit or miss.
The job market, already hit or miss, would likely be put on pause.
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sicily 1003. Hit or Miss
1003. Hit or Miss
Constraints
Time Limit: 1 secs, Memory Limit: 32 MB
Description
One very simple type of solitaire game known as &Hit or Miss& (also known as &Frustration,& &Harvest,& &Roll-Call,& &Talkative&, and &Treize&) is played as follows: take a standard deck of 52 playing cards four sets of cards numbered 1 through 13 (suits
do not matter in this game) which have been shuffled and start counting through the deck 1, 2, 3, . . . , and so on. When your count reaches 13, start over at 1. Each time you count, look at the top card of the deck and do one of two things: if the number
you count matches the value of the top card, disc if it does not match it, move that card to the bottom of the deck. You win the game if you are able to remove all cards from the deck (which may take a very long time). A version of this
game can be devised for two or more players. The first player starts as before with a 52 card deck, while the other players have no cards initially. As the first player removes cards from her deck, she gives them to the second player, who then starts playing
the same game, starting at count 1. When that player gets a match, he passes his card to the third player, and so on. The last player discards matches rather than passing them to player 1. All players who have cards to play with perform the following 2-step
cycle of moves in lockstep: 1. Each player says his or her current count value and checks for a match. If there is no match, the top card is moved to th otherwise it is passed to the next player (or discarded if this is the last player).
2. Each player except the first takes a passed card (if there is one) and places it at the bottom of his or her deck. These rules are repeated over and over until either the game is won (all the cards are discarded by the last player) or an unwinnable position
is reached. If any player ever runs out of cards, he waits until he is passed a card and resumes his count from where he left off. (e.g., if player 3 passes his last card on a count of 7, he waits until he receives a card from player 2 and resumes his count
with 8 at the beginning of the next 2-step cycle).
Input will consist of multiple input sets. The first line of the file will contain a single positive integer nindicating the number of input sets in the file. Each input set will be a single line containing 53 integers: the first integer will indicate the
number of players in the game and the remaining 52 values will be the initial layout of the cards in the deck, topmost card first. These values will all lie in the range 1 . . . 13, and the number of players will lie in the range 1. . . 10.
For each input set, output the input set number (as shown below, starting with 1) and either the phrase &unwinnable& or a list showing the last card discarded by each player. Use a single blank to separate all outputs.
Sample Input
4 1 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 11 12 13
4 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 11 12 13 1
Sample Output
Case 1: 13 13 13 13
Case 2: unwinnable
又臭又长的题目
a)第一个玩家拥有全部的52张牌，而其他的玩家暂时没有牌在手上
b)每一个玩家各自报数，若报的数与牌堆顶上的牌数字相同即为match
c)每个玩家各自报数，各自匹配；
也即是说，A报一个数并记住，比较牌堆顶上的牌，
接着是B报自己的数，比较自己牌堆顶上的牌，以此下去
d)报数均从1开始，若没有牌在手上则不报数，
待至有牌在手上时将上次所报之数加一作为此次的报数
e)若某个玩家（非最后一个玩家）匹配了一次，也就是说报得数跟牌堆上的数字一样时，
将此牌放入下一个玩家的牌堆的最底层； &
如果是最后一个玩家，则丢弃该张牌。 &
若玩家不匹配，也就是说报得数跟牌堆上的数字不一样时，将该牌放入自己牌堆的最底层
f)记录由最后一个玩家丢弃了的牌数，到达52即结束；
g)如果循环到一定次数游戏还没有结束，就可认定无法胜出，跳出。
#include &iostream&
#include &deque&
#include &memory.h&
#include &cstdio&
int main()
std::cin &&
for (int i = 1; i &= ++i) {
std::cin && //the total of players
std::deque &int& players[num]; //the cards of the player
for (int c = 0; c & 52; ++c) {
std::cin &&
players[0].push_back(key);
int count[num], last[num];
memset(count, 0, sizeof(count));
int flag = 0;
int times = 20000;
while (times) {
for (int c = 0; c & ++c) {
if (flag == 52)
if (!players[c].empty()) {
count[c]++;
if (count[c] == 14)
count[c] = 1;
last[c] = players[c].at(0);
players[c].pop_front();
if (count[c] == last[c]) {
if (c != num - 1)
players[c + 1].push_back(last[c]);
players[c].push_back(last[c]);
if (flag == 52)
bool judge =
for (int c = 0; c & ++c)
if (!players[c].empty()) {
printf(&Case %d:&, i);
if (judge) {
for (int c = 0; c & ++c)
printf(& %d&, last[c]);
printf(& unwinnable&);
printf(&\n&);
//std::cin &&
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Q1003: Hit or Miss
&&&&4 1 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 11 12 13
&&&&4 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 11 12 13 1 2 3 4 5 6 7 8 9 10 11 12 13 1
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